Last problem I need help with! Please click attached
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OpenStudy (anonymous):
OpenStudy (anonymous):
<a,b>°<c,d> = implies the two are perpendicular
OpenStudy (anonymous):
=0
OpenStudy (anonymous):
Let a= - xi+2j and b =3i+12j
In order for the two vectors to be perpendicular, the product of their slopes must be -1.
So slope of a = -2/x and slope of b = 12/3= 4
slope of a * slope of b = (-2/x)*4 = -1 so x = 8.
OpenStudy (anonymous):
I think it is vector product problem.
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OpenStudy (anonymous):
By the way i forgot to mention how i got the slope.
It is the vertical component/horizontal component, that is
slope =(coefficient of j/coefficient of i)
OpenStudy (anonymous):
And another way to do it is through dot product.
a.b = 0 since cos90 = 0
So (-3x)i+24j = 0 and taking the magnitude, and simplifying, we get x=8.
OpenStudy (anonymous):
@kartiksriramk ah! you got me!
OpenStudy (anonymous):
This one looks good to me..
OpenStudy (anonymous):
@muhammad9t5 ;)
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OpenStudy (anonymous):
When two vectors A and B are perpendicular then there dot product will be 0..
\[vectors(A \cdot B) = ABcos(90) = 0\]