Last problem I need help with! Please click attached
<a,b>°<c,d> = implies the two are perpendicular
=0
Let a= - xi+2j and b =3i+12j In order for the two vectors to be perpendicular, the product of their slopes must be -1. So slope of a = -2/x and slope of b = 12/3= 4 slope of a * slope of b = (-2/x)*4 = -1 so x = 8.
I think it is vector product problem.
By the way i forgot to mention how i got the slope. It is the vertical component/horizontal component, that is slope =(coefficient of j/coefficient of i)
And another way to do it is through dot product. a.b = 0 since cos90 = 0 So (-3x)i+24j = 0 and taking the magnitude, and simplifying, we get x=8.
@kartiksriramk ah! you got me!
This one looks good to me..
@muhammad9t5 ;)
When two vectors A and B are perpendicular then there dot product will be 0.. \[vectors(A \cdot B) = ABcos(90) = 0\]
Thank you guys!
You're welcome.
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