roots for a quadratic equation using the quadratic formula:
\[32x ^{2}+100x+63\]
Must be equal to 0..
formula :\[\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]
o yes sorry forgot the zero
Yes.. Can you use this formula??
what they said factor.. not find the roots
can i still use the formula?
But read your question..
Question is to find the roots..
i made a mistake, the book said factor the give trinomial
Normal factorization becomes lengthy I guess..
yes but using the formula would be wrong right? because i used the formula and got it wrong until I did normal factorization..
\(32*63 = 2016\) Can you make its factors such that sum will be 100..
okay, i did that but why did you multiply the coefficients?
See in case: \[ax^2 + bx + c = 0\] If a is 1, then we simply make factors of c.. If a is not 1 then we should make factors of ac..
oh yes: ____ x____ = ac __ + ____= b
Yep..
Got the factors or not? I have got.. But I will let you try once..
okay I got the answer using another method: factors of 32: (1,32) (4,8) (2,16) factors of 63: (1,63) (9,7) etc then multiply the factors: (4)(7) + (9)(8) = b = 100 then xs together and ys together (4x+9)(8x+7) =)
I got the factors as 28 and 72.. Yes you got the same..
okay thank you :)
Well Done you are right..
Welcome dear..
thank you, I think what confused me was the factoring and the roots.. because when I used the formula it came out wrong
Using quadratic formula ??
yes, maybe I went wrong somewhere.. but if I used the formula I was looking for roots and not factors
Let me check..
okay (:
\[D = b^2 - 4ac = 1936\] \[\sqrt{D} = \sqrt{1936} = 44\] \[x = \frac{-100 \pm 44}{2 \cdot 32}\] \[\implies x = -\frac{9}{4}\] \[\implies x = -\frac{7}{8}\] Yes it is coming right..
okay you are write, I was getting weird decimals thats why.. so either method works :)
They are both same.. This will never happen that you will get different answers for both.. Remember this..
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