Integrate sin(x^2) wrt x.

Question

shubhamsrg · Answer

hint:
use this 
cos2x = 1- 2sin^2x 
;)

anonymous · Answer

do u know that sin^2a=(1-cos2a)/2

anonymous · Answer

isn't that$$\int \sin x^2 dx$$?

shubhamsrg · Answer

ohh..hahaha..lol.. really sorry...must be what you are saying..hmm..

anonymous · Answer

there is no closed form for this integral...we can do it numerically...

anonymous · Answer

substitute sinx^2 with  (1-cos2x)/2

shubhamsrg · Answer

yes,,no elementary soln..

shubhamsrg · Answer

well if you apply limits surely an ans is there..

anonymous · Answer

but there is an interval that this integral can be done analytically...and that is$$\int_{0}^{\infty} \sin x^2 dx$$

anonymous · Answer

o.0 just substitute sinx^2 with (1-cos2x)/2 and integrate two parts ...
(1/2)dx  and    (cos2x/2)dx

anonymous · Answer

@protosbg 

thats $\sin x^2$  not  $\sin^2 x$

anonymous · Answer

anonymous · Answer

lol :D sorry

shubhamsrg · Answer

how about simpson's rule here?? we may take limits a to b,,any arbitrary constants..

anonymous · Answer

Mukushla, what is the proof of the thing after <>?

anonymous · Answer

we must make it a double integral...and change it from cartesian to polar...

anonymous · Answer

and we will treat $t$  like a constant here

anonymous · Answer

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