Question

Hey can anyone help???
how do you find the center and the radius of this equation, (x-1)^2+y^2=24

Answer 1

General form of the equation of a circle is:
\[(x-h)^{2}+(y-k)^{2}=r^{2}\]
Where
(h,k) is the center and the radius is r

Now, what values do you have for h, k, and r? :)

Answer 2

center= (1,0) and radius =\[\sqrt{24}\]

Answer 3

how am i suppose to put it into standard form if i only have y^2 and no other y values??

Answer 4

(x-1)^2+(y-0)^2=24

Answer 5

oh so you sub 0 in if you dont have the other value you need??

Answer 6

yes

Answer 7

ok that makes much more sense.