Use a calculator or CAS to evaluate the line integral correct to four decimal places. \[\int_c F\cdot dr\] where \[F(x,y)=xy\hat i+siny \hat j\] and \[\hat r(t)=e^t\hat i+e^{-t^2} \hat j\] \[1\le t\le 2\] I tried using this: http://kevinmehall.net/p/equationexplorer/vectorfield but it doesn't seem to be working.
I am gonna look at my old notes from Calc III
I can do it manually, but how do I do it using a calculator?
what's x and y?
\[\hat r '(t)=e^t\hat i-2e^{-t^2}\] \[x=e^t\] \]y=e^{-t^2}\]
\[ y=e^{-t^2}\]
Ah i see. So I would set up the integral manually and then plug it into wolfram. Thank you!
well , I had it find dot product too
Turing, can I get a quick tutorial on how to plug this into wolfram?
Libniz seems to know better than I I didn't know you could just write "dot" and get a dot product :P
I would have just done the dot product be hand, then written "integrate ....dt from 1 to 2"
is it something along the lines of integrate[Dot[{F( r(t))},{ r'(t)}],{t,1,2}]
I think that's right
ah libniz I do think you forgot to find r'
you don't need that when dealing with vector
but yeah, that seems to be how it's typed
\[\int\limits_C\vec F\cdot\vec r(t)dt=\int_a^b\vec F(\vec r(t))\cdot\vec r'(t)dt\]
indeed
that's what I would think @TuringTest
now Libniz and I agree we just missed the r' earlier
oh yeah looks like you both came up with 1.9633
yup
Thanks y'all!
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