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Mathematics 21 Online
OpenStudy (anonymous):

Solve the absolute value inequality: |5x + 3| 13

OpenStudy (ghazi):

is there a sign between quantity in mod and 13

OpenStudy (anonymous):

was gonna ask the same question

OpenStudy (anonymous):

yes sorry its greater than or equal to

hero (hero):

\(|5x + 3| \ge 13\) I usually do this as the next step even though it is not exactly legal: \(-13 > 5x + 3 > 13\) Then afterwards, I break that off into two separate equations: \(5x + 3 > 13 \\ 5x + 3 < -13\)

hero (hero):

So that second step is something I kinda do on the side when no one is looking just so I can know which way to place the signs.

OpenStudy (anonymous):

yes, when no one is looking...

hero (hero):

I knew you were going to say something @satellite73. I know you hate that step.

OpenStudy (anonymous):

whatever works for you, just as long as you move on to the next step immediately, and not try to solve \[-13 > 5x + 3 > 13\] which of course has not solution since \(-13>13\) is patently false

hero (hero):

Yes, I am keenly aware of how not to confuse myself when using it.

OpenStudy (ghazi):

@Ashely3 did you get your solution....?

OpenStudy (anonymous):

so then its x>2 and x>-3.2

OpenStudy (ghazi):

i guess x<2

OpenStudy (ghazi):

and x> -3.2.....so it's -3.2<x<2

hero (hero):

@Ashely3, I hope @satellite73 intrusion didn't confuse you. What I posted is an approach that you can use to keep up with the signs. 5x+3>13 5x+3<−13 This, what I posted above are definitely the way the signs should be.

hero (hero):

Satellite has an issue with when I post the equation as a conjuction: -13>5x + 3 > 13 This is the part that is not legal, however, it is a way to keep with the signs, which is really the most important thing.

OpenStudy (anonymous):

x -3.2 or x 2

OpenStudy (anonymous):

so is this it

hero (hero):

I still don't see your signs. You should use the keyboard. Your keyboard has >< signs believe it or not. At least it is supposed to have them.

OpenStudy (anonymous):

x less than or equal to -3.2 or x greater than or equal to 2

hero (hero):

Yes, correct

OpenStudy (anonymous):

yay

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