Solve the absolute value inequality: |5x + 3| 13
is there a sign between quantity in mod and 13
was gonna ask the same question
yes sorry its greater than or equal to
\(|5x + 3| \ge 13\) I usually do this as the next step even though it is not exactly legal: \(-13 > 5x + 3 > 13\) Then afterwards, I break that off into two separate equations: \(5x + 3 > 13 \\ 5x + 3 < -13\)
So that second step is something I kinda do on the side when no one is looking just so I can know which way to place the signs.
yes, when no one is looking...
I knew you were going to say something @satellite73. I know you hate that step.
whatever works for you, just as long as you move on to the next step immediately, and not try to solve \[-13 > 5x + 3 > 13\] which of course has not solution since \(-13>13\) is patently false
Yes, I am keenly aware of how not to confuse myself when using it.
@Ashely3 did you get your solution....?
so then its x>2 and x>-3.2
i guess x<2
and x> -3.2.....so it's -3.2<x<2
@Ashely3, I hope @satellite73 intrusion didn't confuse you. What I posted is an approach that you can use to keep up with the signs. 5x+3>13 5x+3<−13 This, what I posted above are definitely the way the signs should be.
Satellite has an issue with when I post the equation as a conjuction: -13>5x + 3 > 13 This is the part that is not legal, however, it is a way to keep with the signs, which is really the most important thing.
x -3.2 or x 2
so is this it
I still don't see your signs. You should use the keyboard. Your keyboard has >< signs believe it or not. At least it is supposed to have them.
x less than or equal to -3.2 or x greater than or equal to 2
Yes, correct
yay
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