Why don't you add the answer to this equation..?
\[7/2+\sqrt{5}\] Answer: \[-14+7\sqrt{5}\]
this looks more like:\[\frac{7}{2+\sqrt{5}}\]
I assume the problem is \[ \frac{7}{2+\sqrt{5} } \]
in which case you just multiply the numerator and the denominator by \((2-\sqrt{5})\)
that will get rid of the radicals in the denominator
I know how to solve it, I just wanna know if I should add -14+7?
no you cannot add \(7\sqrt{5}\) and \(-14\)
if it was:\[-14\sqrt{5}+7\sqrt{5}\]then you could add them
to get: \(-7\sqrt{5}\)
think of it like this, suppose you had:\[3+4\times7\]that is NOT the same as: \((3+4)\times7\)
whereas if you had:\[3\times7+4\times7\]then that DOES simplify to: \((3+4)\times7\)
yet another way to look at this is to replace the \(\sqrt{5}\) with \(x\) to get:\[-14+7x\ne-7x\]
since they are NOT "like" terms
hope that makes sense
you can combine them as a decimal (approximately) -14+7*sqrt(5) is about 1.65247584
Ohh, okay. Yeah, it makes sense. Thanks!
yw :)
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