Question

find the domain of this function? explain please. noncalculator

f(t)= ∛(t-1)

Answer 1

we are looking for what the x's can be. is there any reason that x cant be a certain number or numbers?

Answer 2

i honestly don't know

Answer 3

it can be anything so its just negative infinity and infinity

Answer 4

(-oo,oo)

Answer 5

yes (-infinity,infinity)

Answer 6

or {x:x is an element of R}

Answer 7

thanks sometimes these are so easy i over think them haha

Answer 8

np, the only time you will run into problems with roots is when the root is even, do you understand why?

Answer 9

no could you explain

Answer 10

like there is one ezample

Answer 11

quadroot of (x^2-6x)

Answer 12

i think its called a quad root hahaha

Answer 13

right, so what is the domain of \[\sqrt[4]{x}\]?

Answer 14

You can't take the square root of a negative number because you can't ever multiply something by itself and get a negative number! -1*-1=1 and 1*1=1

You also can't divide by 0.

Answer 15

so notice sqrt(-1) = 4th root of(-1) = 6th root of (-1) = i

Answer 16

couldnt it be -oo,oo

Answer 17

no, can you take the 4th root of -5?

Answer 18

in other words a*a*a*a = -5 whats a?

Answer 19

\[\sqrt[even number]{x} \] is undefined when x <0
\[\sqrt[odd number]{x} \] is defined for all real numbers
(notice i is not a real number)

Answer 20

look at the graph, notice all of the x's are used on the number line
that is why it is "all real numbers" for the domain
aka as (-infinity, +infinity)

Answer 21

i'm still lost.

Answer 22

sorry

Answer 23

ok lets do one
this is a line segment