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Mathematics 14 Online
OpenStudy (anonymous):

Find the slope of the line shown on the graph. Have the picture of the graph attached to a response.

OpenStudy (anonymous):

OpenStudy (anonymous):

slope of the line right??

OpenStudy (anonymous):

Yes, I need to find it.

OpenStudy (anonymous):

okay slope is raise/ run and that is delta x / delta y do you recall this

OpenStudy (anonymous):

Yes, but forgot how to do it.

OpenStudy (anonymous):

so therefor it's slope= delta x/delta y (y1-y2) /(x1-x2) does this help?

OpenStudy (anonymous):

So, I look to see what each point is?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

recall that on the x y graph y1 and x1 must the on that line it doesn't matter which is y1 or x1 it just matters it's X and Y and than plug in and solve

OpenStudy (anonymous):

Ok, so the graph shows the first point is on the y axis 2. So it would be (0,2) and the other is (5,0)?

OpenStudy (anonymous):

right so use the formula I just gave you, in this case I am sorry it will matter which is 1for y and x in this problem.

OpenStudy (anonymous):

So far I got \[2 \over 5 \]

OpenStudy (anonymous):

that is the slope of that line

OpenStudy (anonymous):

So - \[2 \over 5\]

OpenStudy (anonymous):

Thanks. :)

OpenStudy (anonymous):

do you mean -2/5?

OpenStudy (anonymous):

Yeah, don't know why it went like that.

OpenStudy (anonymous):

hint look at which the line is angled on the graph if it is right to left most likely + if the line goes from left to right angle it is negative

OpenStudy (anonymous):

another clue where does the line cross the y at if it's at - than it is negative

OpenStudy (anonymous):

make sense??

OpenStudy (anonymous):

meant to say x not y

OpenStudy (anonymous):

Yeah, now just to figure this next one out, one of the y's is negative and the other is positive and both x's are positive.

OpenStudy (anonymous):

what is the problem asking for??

OpenStudy (anonymous):

SLope again lol. (4,0) and (0,-5)

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

does it anything like MX+B point slop form? just checking.

OpenStudy (anonymous):

Just asks to find to slope if it exists of the line.

OpenStudy (anonymous):

okay than..

OpenStudy (anonymous):

If i am doing this right, there is no slope.

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

or we say undefined

OpenStudy (anonymous):

because if you divide by 0 it is undefined

OpenStudy (anonymous):

ex 0/2 that would be undefined

OpenStudy (anonymous):

Alright. And I hate when it does these problems in a row. now it is (2,-9) and (-2,-9) Which is: \[0 \over -4\]

OpenStudy (anonymous):

ask yourself can divide 0/-4 if the answer is no than it is undefined

OpenStudy (anonymous):

also keep in this mind when doing these, ******** the first number is always always X and the second number is always Y DON"T REVERSE THEM!!! :)

OpenStudy (anonymous):

0/-4 would be 0 if I do that correctly. I always get the division mixed up for some reason.

OpenStudy (anonymous):

let us back up for one min here, if I gave (1,-5) and (9,0) which number is the x and Y?

OpenStudy (anonymous):

Y is -5 and 0. X is 1 and 9.

OpenStudy (anonymous):

that is how you enter them into the slope formula.

OpenStudy (anonymous):

so the one would X1 and the -5 would be Y1

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