Question

i need work shown step by step can someone please help me??

Answer 1

x^(2)+x=12

Answer 2

how do you get rid of the ^2 . Do you remember from the Pythagorean Theorem?

Answer 3

no

Answer 4

wait why the pythagoreon theorem??? @cocoa020

Answer 5

oh nm...
ignore me :/

Answer 6

you square root it \[\sqrt{x}\]

Answer 7

i need the problem shown step by step

Answer 8

because you found the square root of one side, you have to do it on the other

Answer 9

We're doing it step by step:
x^2+x=12
\[\sqrt{x}

Answer 10

excuse me, square root of x square root of 12

Answer 11

I'm really not sure where this is going... :)

Answer 12

I don't think this method works?! If you take square root on both sides, it becomes
\[\sqrt{x^2+x} = \sqrt{12}\] Not easy to solve.

Answer 13

you could also just factor a problem like this instead of squaring the equation....

Answer 14

^^Indeed!, but first, rearrange some terms.

Answer 15

\[x ^{2}+x=12\]bring the 12 over to the other side by subtracting 12 on both sides\[x ^{2}+x-12=0\] now we need 2 numbers that have the product of -12 and the sum of 1

Answer 16

x^(2)+x=12
Subtract 12 from both sides.
x^(2)+x-12=12-12
x^2 + x - 12 = 0
Factor the expression,
x^2 +4x - 3x -12 = 0
x(x+4) - 3(x+4) = 0
(x-3)(x+4) = 0
Put each factor = 0 and solve them, that is
x-3 = 0 or x+4 = 0

Answer 17

so we can get -3 and 4 so...\[(x+4)(x-3)=0\]

Answer 18

then when you solve it you would get the zeros as -4 and 3

Answer 19

^ Don't give answers, thanks!