CAN SOMEONE HELP ME ON MY PHYSICS HOMEWORK. v^2 = v0^2 + 2as - S0

Question

CAN SOMEONE HELP ME ON MY PHYSICS HOMEWORK.  v^2 = v0^2 + 2as - S0

theeric · Answer

What do you need help with?

theeric · Answer

$$ v^2 = v_0 + 2as - s_0$$

theeric · Answer

That's it, right?

shane_b · Answer

$$\large v_{final}^2=v_{initial}^2+2a\Delta s$$

theeric · Answer

That looks better. :)

shane_b · Answer

Clearer in my mind also :)

anonymous · Answer

YES @theEric

theeric · Answer

I agree with Shane_B.

shane_b · Answer

The only issue with @theEric's and your equation is that "+2as-s0" should be "+2a(s-s0).  

In my equation, I just simplified that to delta s.

theeric · Answer

I also forgot to square initial velocity!

shane_b · Answer

Ahh...I missed that !

theeric · Answer

And I agree with your alteration, because that's the formula that is built into my memory.

shane_b · Answer

It's less to memorize also :)

anonymous · Answer

i got v^2- vo^2 +s0/2s is this right

shane_b · Answer

That's not an equation though...what are you trying to solve for?

theeric · Answer

Since there isn't an equal sign ("="), it can't be evaluated to true or false.

theeric · Answer

$$v_{final}^{2} - v_{initial}^{2}-2a \Delta s = 0$$

theeric · Answer

I believe that's correct. It's your expression being equal to zero. It was formed by manipulating the formula
$$v_{final}^{2} = 2_{initial}^{2} + 2 a \Delta s$$

theeric · Answer

Pfft! Messed it up again!

theeric · Answer

$$v_{final}^2 = v_{initial}^2 = 2\Delta s$$

shane_b · Answer

I think you did it again...the left "=" should be a "-" sign :)

shane_b · Answer

Or I guess..the right "=" sign should be a "+"

theeric · Answer

Hahaha, either one! :) I should stop making equations! :P