I need an example of a union of 2 subgroups that isnt a subgroup
It sounds more confusing than it is Basically H and K are subgroups of G but \( H \cup K \) isnt a subgroup of G
what groups do you know?
I know nothing
Cyclic groups
and that is it
if you pick two subgroups of \(S_3\) and take there union it will not be a subgroup
but that one is not cyclic how about the group \(\mathbb{Z}\) under addition
ohhhhh It doesnt have to be cyclic
subgroups of \(\{\mathbb{Z},+\} \) look like what?
Yeah, I can't think how this is even possible...
it is. I am in middle of working on \( (\mathbb{Z_4}, +) \)
yeah. I am really weak on Set Theory. Next thing to brush up on...
I am weak on everything -_-
subgroups of \(\{\mathbb{Z},+\}\) look like \(n\mathbb{Z}\)
\[ A= 5 Z\\ B=7 Z\\ 5 \in A \cup B\\ 7 \in A \cup B\\ but\\ 5+7 \notin A \cup B\\ \]
huh I had a totally diff example
I dont get it what u guys r doing
so take for example the union of two such subgroups, say \(7\mathbb{Z}\) and \(5\mathbb{Z}\)
oh wow i am being a copy cat, i guess it was the easiest answer
lol
is it clear what i wrote (after @eliassaab wrote the same thing first?)
Like i dont get ur notation. They dont show any of that in my book
But I have another exxample
as subgroup of \(\mathbb{Z}\) under addition looks like all multiples of some number say 5 so it would be the set \(\{...-15,-10,-5,0,5,10,15,...\}\)
okk
you can check that this is a subgroup easily now pick another such subgroup because apparently i have no originality pick \[7\mathbb{Z}=\{...-21,-14,-7,0,7,14,21,...\}\]
their union is what? all multiples of 5 or 7 but it is not even closed, since \(5+7\) is not in there
ohhhhh i get ittttttt
Thanksss idk all i see in my book are these mod examples so i just used one of those
Thankkkssssss guys
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