Question

log_8*2/128=2x-30

Answer 1

base 8 ?

Answer 2

\(\huge \log_8 \frac{2}{128} = 2x-30\)

like this ?

Answer 3

Correct. Can u answer.

Answer 4

first simplify log

Answer 5

2/128 = 1/64 = 8^2

Answer 6

=>

\(\huge \log_8 \frac{1}{8^2} = 2x-30\)

Answer 7

umm ok makes sense

Answer 8

next, write 1/8^2 as 8^-2

Answer 9

\(\huge \log_8 8^{-2} = 2x-30\)

Answer 10

can you solve from here ?

Answer 11

let me see fast

Answer 12

ok, good luck :)

you can use the log property :
\(\log a^m = m \log a\)

Answer 13

ok thanks for the equation

Answer 14

np...

Answer 15

-8 on the left side 8^-8=1/64

Answer 16

hmm nopes

Answer 17

\(\huge \log_8 8^{-2} = 2x-30\)

\(\huge -2*\log_8 8 = 2x-30\)

Answer 18

another log property is :
\(\log_a a = 1\)

Answer 19

so that log expression simplifies to 1

Answer 20

ok -2 that was my next guess when u wee typing

Answer 21

\(\huge -2*1 = 2x-30\)

\(\huge -2 = 2x-30\)


you can solve for x now