Determine the domain of the function. f(x) is equal to the square root of two minus x. x ≤ 2 All real numbers x > 2 All real numbers except 2
\[f(x)=\sqrt{2-x}\]
Hint: You cannot take the square root of a negative number (and get some real number)
So the radicand (the stuff inside the square root) can't be negative
can you please teach me how to do this step by step PLEASE
Similar example: Find the domain of \[\Large g(x) = \sqrt{x+3}\] You can't take the square root of a negative number, so the radicand must be either 0 or positive. So... \[\Large x+3 \ge 0\] \[\Large x+3-3 \ge 0-3\] \[\Large x \ge -3\] is the domain
but its positive ??
I'm not sure what you mean
you said you can't take the square root of a negative number
yes exactly, so whatever number that is in the square root is either a) zero or b) positive
if your finding the domain of a square root your rules are that the number cant be negative. if you were taking the domain of a fraction the rules would be you cant have a zero on the denominator
is the answer x ≤ 2
correct! good work !!
i missed you @ganeshie8
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