A point charge +10 μC is a distance 5 cm directly above the centre
of a square of side 10 cm, as shown in Fig. 1.34. What is the
magnitude of the electric flux through the square?

Question

A point charge +10 μC is a distance 5 cm directly above the centre
of a square of side 10 cm, as shown in Fig. 1.34. What is the
magnitude of the electric flux through the square?

maheshmeghwal9 · Answer

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maheshmeghwal9 · Answer

I only understood this much : -$$\text{Charge}=+10 \mu C=+10^{-5}C.$$$$\text{Distance}=5cm.=0.05m.=5\times 10^{-2}m.$$$$\text{Square's Side}=10cm.=0.1m.=10^{-1}m.$$
Now Wt should I do?
Please help:)

ghazi · Answer

The square can be considered as one face of a cube whose edge is 10 cm with a centre where charge q is placed. According to Gauss’s theorem for a cube, total electric flux is through all its six faces.
$$\phi = q/\epsilon $$ but through one face that is the square, it will be $$\phi= \phi/6= q/\epsilon*6$$ now just substitute the value of q and epsilon you'll get flux through square

anonymous · Answer

http://www.youtube.com/watch?v=XaaP1bWFjDA&feature=bf_prev&list=SPC2CEECFD938FD494 Once again, Walter Lewin explains a concept excellently.