Question

plot the graph of the relation:

Answer 1

\[y=\frac{ 2 }{ \sqrt{x+1} }\]

Answer 2

my intercepts: y=0 ---> \[\sqrt{x+1}=2\]
x+1=4
x=3
x=0 ---> y=2 is that right?

Answer 3

yes

Answer 4

okay and we have a vertical asymptote at x=-1

Answer 5

@waterineyes @panlac01

Answer 6

yes u have asymptote.. bcoz x=-1 makes the denominator 0