Question

another graph the relation:

Answer 1

\[y=\frac{ x(x+2) }{ x+3 }\]

Answer 2

intercepts:
x= 0 y=0
y=0 x=>x^2+2=0 --> x^2= -2 then?

Answer 3

@waterineyes , @ganeshie8 @Tushara

Answer 4

vertical asymptote where the denominator is 0, i.e. at \(x=3\)

Answer 5

oops i meant \(x=-3\)

Answer 6

y=0
0 = x(x + 2)

Answer 7

\(x(x+2)=0\implies x=0\) or \(x=-2\)

Answer 8

slant asymptote as well

Answer 9

since the numerator degree is 1 greater than the denominator
so i divide N/D right?

Answer 10

yes divide, get a degree one polynomial (aka a line) and a remainder. the line is the slant asymptote, ignore the remainder

Answer 11

okay :) thank you!

Answer 12

yw

Answer 13

@satellite73 the S.A is x-1?

Answer 14

\(y=x-1\) yes you have it

Answer 15

okay :)