Two cars of masses m1 and m2 are moving in a circle of radii r1 and r2 , respectively. Their speeds are such that they make complete circles in the same time t.The ratio of their centripetal acceleration?
@ajprincess
is the ans p1/p2 ? where p=momentum ?
ac = v^2/r
no the answer is m1 r1 : m2 r2
i wonder hw that mass came there
becoz centripetal force = mv^2/r.......but the question asks for centripetal acceleration
shouldnt ans be m1v1 / m2v2 ?
instead of r1 ?
and r2 *
i am confused
see a1 = m1(v1)^2 / r1 and a2 = m2(v2)^2 /r2 you have to find a1/a2 = (m1v1 / m2v2) * ( v1r2 / v2r1) now t = 2pi r1/v1 = 2pi r2/v2 =>v1r2 = r1v2 so req ratio = m1v1 / m2v2
first of all @shubhamsrg centripetal acceleration = v^2/r
ohh yes..sorry..
really sorry..
well v1 and v2 are not mentioned in the ques..and ans comes out to be v1/v2 we need to fine a relation between m,v and r now..hmm..
i dont see mass coming from any where.. since v1/v2 = r1/r2 i'd say thats the ans..
Accelerations are independent of mass.It might be given to confuse you. Anyway,Since the cars take the same time to go around the circle, angular velocity = 2*pi/t = same for both cars. Let the centripetal accelerations be a1 and a2.v= r *angular velocity. a1 = v1^2/r1 = r1*(angular velocity)^2, a2 = v2^2/r2 = r2*(angular velocity)^2 a1/a2 = r1/r2 .
@kartiksriramk but in the book it is given as m1 r1 : m2 r2
Please check it again.I am pretty sure that the ratio is r1/r2.
i also got that...... the options ar r1 : r2 , m1r1:m2r2
Then it is definitely r1 : r2 .
but the answer is given as m1r1:m2r2
It must be wrong.
i dont think
i will show the proof
Okay.
AIEEE question
and this is a model answer paper
Did you check the answer key?
he may be wrong @kartiksriramk
they have same angular velocity,|dw:1345129570006:dw| hence the required result follows
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