Mathematics
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OpenStudy (anonymous):
Using complete sentences, explain how to find the zeros of the function f(x) = 2x^3-9x+3.
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OpenStudy (anonymous):
well I think you factor out the equation and use the ( ? ) ( ? ) to solve for x, whatever the x's are will be your zeros
OpenStudy (anonymous):
what is the (?)(?)
OpenStudy (anonymous):
factorize first
OpenStudy (anonymous):
how
hero (hero):
Start by finding two numbers, a and c, such that:
a + c = -9
ac = (2)(3)
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hero (hero):
Or you can just graph the function and observe where it crosses the x-axis
hero (hero):
Yet another alternative is to complete the square. If you want to do that, you can start by setting f(x) to 0.
hero (hero):
2x^2 - 9x + 3 = 0
OpenStudy (anonymous):
hero (hero):
One of the above are methods students use to find the zeroes.
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hero (hero):
Okay, that's a good start.
OpenStudy (anonymous):
i cant seem to factor the 2x^2 - 9x + 3 = 0
hero (hero):
That's because it is not factorable by methods you normally use.
hero (hero):
If the quadratic function isn't factorable, you usually use the quadratic formula to find the zeros.
hero (hero):
\(\large x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
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OpenStudy (anonymous):
im doing that right now
hero (hero):
Great :D
OpenStudy (anonymous):
\[9+√57/4 \]
OpenStudy (anonymous):
\[9-√57/4\]
hero (hero):
And that's still simplifyable
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OpenStudy (anonymous):
ohh
hero (hero):
Did you figure out your mistake while using the formula?
OpenStudy (anonymous):
nope
hero (hero):
looks like I'm the one that made the mistake.
hero (hero):
Good job
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OpenStudy (anonymous):
hahaha thanks!