Question

How to approach this calc problem?
See attached.

Answer 1

integral from x=a to x=b is equivalent to the area under the curve
area below the x-axis is negative
in this case area (integral) can be found by looking at the area geometrically and adding (or possibly subtracting) the rectangles

Answer 2

so would the area just be 2 + whatever the integral of y = -2 from (2,6] is + whatever the integral of y = 3 from (6,10] is? the fact that 6 has both an open and a closed circle at its point means something but I can't get any further than that

Answer 3

I don't know how to work the open circles

Answer 4

the solid circle means the value at x is the plotted y value
the open circle means that the function does not have a defined value at the plotted (open circle) point. (but the solid circle at the same x does define the y value)

Answer 5

or, x approaches the value of the open circle.

Answer 6

Yes I realize that

Answer 7

so the point of the open/closed circles to make sure there is only 1 y value to the plotted points.

0≤x ≤ 2
2 < x ≤ 6
6 < x ≤ 10

Answer 8

Thanks anyways, got it on my own