Question

how do u make 'h' the subject of A=πr^2+2πrh ?

Answer 1

you've to make h subject of what?

Answer 2

It simply concludes that we have to solve for h

Answer 3

Subtract \(\pi r^2\) both the sides first..

Answer 4

Then divide by \( 2 \pi r\) you will get h as subject..

Answer 5

\[\large{A=\pi r^2 +2\pi rh}\]
\[\large{A-\pi r^2=\pi r^2-\pi r^2+2\pi rh}\]

what do you get? @karenw12

Answer 6

Subtract πr2 to balance out the equation

Answer 7

right

Answer 8

so what do you get?

Answer 9

will it be :
\[\large{A-\pi r^2=2\pi rh}\]?

Answer 10

yes

Answer 11

no?

Answer 12

Just kidding @mathslover

Answer 13

\[\large{A-\pi r^2=\cancel{\pi r^2}\cancel{-\pi r^2}+2\pi rh}\]
\[\large{\frac{A-\pi r^2}{2\pi r}=\frac{2\pi rh}{2\pi r}}\]

what do you get now @karenw12 ?