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Mathematics 10 Online
OpenStudy (anonymous):

A bag contains a total of 14 batteries, of which five are defective. Selecting two at random, without replacement, determine the probability that none of the batteries you select are good. 1/2 1/7 10/91 5/14

OpenStudy (phi):

what is the probability the first battery you pick is defective?

OpenStudy (anonymous):

5/14

OpenStudy (phi):

without replacement means you keep the (dead) battery out. How many batteries are in the bag? how many dead batteries are in the bag (assuming you picked a bad one the first time)?

OpenStudy (anonymous):

1/7

OpenStudy (phi):

after you pick a bad battery out of the bag, how many batteries remain in the bag? how bad batteries are in the bag?

OpenStudy (anonymous):

5

OpenStudy (anonymous):

13 rmain

OpenStudy (phi):

13 remain. but only 4 are bad (because we are assuming you pulled a bad one out the first pick) now what is the probability of picking another bad battery out of a bag with 13 batteries, 4 of them bad?

OpenStudy (anonymous):

3/12=1/4

OpenStudy (phi):

now what is the probability of picking another bad battery out of a bag with 13 batteries, 4 of them bad?

OpenStudy (phi):

It is the same problem as 14 batteries, of which 5 are defective. except on the 2nd pick you have 13 batteries, of which 4 are bad

OpenStudy (anonymous):

so what would it be then, im confused?

OpenStudy (phi):

If you are confused, start at the beginning. what is the chance of picking a bad battery from a bag wih 14 batteries, of which 5 are defective.

OpenStudy (cwrw238):

a tree diagram may help |dw:1345140533265:dw|

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