A bag contains a total of 14 batteries, of which five are defective. Selecting two at random, without replacement, determine the probability that none of the batteries you select are good. 1/2 1/7 10/91 5/14
what is the probability the first battery you pick is defective?
5/14
without replacement means you keep the (dead) battery out. How many batteries are in the bag? how many dead batteries are in the bag (assuming you picked a bad one the first time)?
1/7
after you pick a bad battery out of the bag, how many batteries remain in the bag? how bad batteries are in the bag?
5
13 rmain
13 remain. but only 4 are bad (because we are assuming you pulled a bad one out the first pick) now what is the probability of picking another bad battery out of a bag with 13 batteries, 4 of them bad?
3/12=1/4
now what is the probability of picking another bad battery out of a bag with 13 batteries, 4 of them bad?
It is the same problem as 14 batteries, of which 5 are defective. except on the 2nd pick you have 13 batteries, of which 4 are bad
so what would it be then, im confused?
If you are confused, start at the beginning. what is the chance of picking a bad battery from a bag wih 14 batteries, of which 5 are defective.
a tree diagram may help |dw:1345140533265:dw|
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