Question

The average (arithmetic mean) of a,b,and c, is equal to the median of a, b,and c. If 0>a>b>c, which of the following must be equal to b?

Answer 1

A. a+c/2
B. a+c/3
C. c-a/2
D. C-A/3
E. Sqrt AC

Answer 2

Given 0>a>b>c. b must be the median.

The average = (a+b+c)/3.

So b= (a+b+c)/3 and solve for b....hint: distribute out the fraction

Answer 3

So would it be B?

Answer 4

b = a/3 + b/3 + c/3 (subtract b/3 from both sides)
2/3b = a/3 + c/3 (multiply 3/2 to both sides)
b = a/2 + c/2
or
b = (a+c) /2

Answer 5

oh i forgot to factor out the /3 along with b.

Answer 6

yep

Answer 7

and this answer makes sense for b to be the average....the average of a and c (a+c/2) must equal b as well

Answer 8

Thank you :)

Answer 9

no problem