Question

PLEASE PLEASE PLEASE HELP!
Complete the proof of the Quotient Rule: logb x/a = logb x – logb a.
Let m = logb a and n = logb x.
Then a =

and x =

By the Quotient Property of Exponents, x/a =

Take logb of both sides to get logb x/a =

Re-substitute for m and n to get logb x/a =

Answer 1

do you know how log is defined?
if you have
\[\log_x y =z\]
what's y here?

Answer 2

@natasha.aries ???

Answer 3

what do you mean?

Answer 4

@ash2326 sorry my computer was working

Answer 5

the answer is probably over 9000

Answer 6

its a proof though

Answer 7

logb x/a = logb x – logb a.
\(\large log_b \frac{x}{a} = log_bx-log_ba\)
Let
\(\large m=log_ba \) and \(\large n=log_bx \)
so
\(\large a=b^m \) and \(\large x=b^n \)

so \(\large \frac{x}{a}=\frac{b^n}{b^m} =b^{n-m}\)
therefore,
\(\large log_b\frac{x}{a}=n-m=log_bx-log_ba \)

Answer 8

thankss!