Question

What is the equation, in standard form, of a vertical hyperbola with asymptotes at y + 8 = ±2/9(x – 8)?

Answer 1

square the slope

Answer 2

this is your a^2 b^2 parts

Answer 3

pull the center from the equation given of the asymptotes

Answer 4

since vertical is up and down, y is +, and x is -

Answer 5

pfft, just use the x and y parts inthe hyper :)

Answer 6

y + 8 = ±2/9(x – 8)

4/81

and since y/x defines slope, then 4 is under ys and 81is under xs

(y+8)^2 (x-8)^2
------- - -------- = 1
4 81

Answer 7

Thank you!