Question

domain:

Answer 1

\[y= \frac{ 1-\sqrt{3x} }{ x ^{17}}\]

Answer 2

the book's answer: domain is > 0 but i don't understand why..

Answer 3

@jim_thompson5910

Answer 4

@Valpey

Answer 5

\[\sqrt{(3x)}\] needs to be positive in order to be defined.

Answer 6

Unless you mean \[\sqrt{(3)}*x\]

Answer 7

oh okay, i thought that its only the denominator that i needed to worry about since its a rational expression.

Answer 8

thank you :)

Answer 9

Right. "Square Root" is a bit of a finnicky function. It is very specifically only defined for non-negative reals.

Answer 10

But the square root allows x=0. It is the denominator which prevents x=0 from being in the domain.