Question

solve 6/x+4=1/2
a: 8
b: -1
c: 16
d: 4

Answer 1

do you mean?
\[\frac{6}{x} + 4 = \frac{1}{2}\]

Answer 2

Hint: Cross Multiply to get

6(2) = x + 4

Answer 3

@Australopithecus nope

Answer 4

\[\frac{6}{x} = \frac{1}{2} - 4\]
\[(\frac{6}{x})x = (\frac{1}{2} - 4)x\]
\[6 = (\frac{1}{2} - 4)x\]
\[\frac{x}{(\frac{1}{2}-4)} = \frac{(\frac{1}{2} - 4)x}{(\frac{1}{2}-4)}\]

Answer 5

oops

Answer 6

\[\frac{6}{\frac{1}{2} - 4} = x\]

Answer 7

that last equation should have a 6 above it instead of an x

Answer 8

@Australopithecus i'm confused

Answer 9

@Australopithecus made an incorrect assumption it seems

Answer 10

\(\huge\frac{6}{x+4} = \frac{1}{2}\)

Answer 11

^Cross multiply that to get

6(2) = x + 4

Then solve for x

Answer 12

@Hero so A ?

Answer 13

Correct @keana

Answer 14

\[\frac{6}{x+4} = \frac{1}{2}\]
\[\frac{6}{x+4}(x+4) = \frac{1}{2}(x+4)\]
\[\frac{6}{x+4}\frac{(x+4)}{1} = \frac{1}{2}\frac{(x+4)}{1}\]
\[\frac{6(x+4)}{1*(x+4)} = \frac{(x+4)*1}{2*1}\]
\[6 = \frac{x+4}{2}\]
\[6(2) = \frac{(x+4)2}{2*1}\]
\[6(2) = x+4\]
\[6(2) - 4 = x\]