Solve 7.74x + 3 = 10.2
First, subtract 3 from both sides. Let me know what you get.
And then after what hero said, divide by 7.74
One step at a time @Veelution
7.74x= 7.20
Great. Now, as Veelution said, divide both sides by 7.74
oh wait ; i wrote the equation wrong : / It's actually 7.7^4x+3=10.2
Wow, that greatly changes the outcome
Take logs of both sides, then
how in the would do i do that ?
i'm sorry , but i reall suck at math -_-
\(\log(7.7)^{4x}= \log(7.20)\)
i know the answer
@Snapbacklive, let me remind you again that giving answers is not helpful. Help students get to the answer, not give them.
i know but i didn't right
No, but you probably wanted to.
@Hero but i can't put the x into the equation in my calculator . so what do i do with it ? & i got the log of 7.20 .
x is nothing
You didn't have to necessarily use your calculator just yet. Usually, you want to wait until you have completely isolated x first.
it's just a sub
ahh , all of this is beyond confusing -_-
But anyway, here's the rule you're looking for @kianalauntra \(\log(b)^a = a \log(b)\)
well it depends
i got that . . .
Okay, here's what you should have at this point: \(4x \log(7.7) = \log(7.20)\)
Do you have an idea of what the next step might be?
do i get the logs of both ?
We should wait until the end before computing logs. For the next step, you want to divide both sides by \(\log(7.7)\). Remember we're trying to isolate x first.
Let me know what you get after dividing both sides by \(\log(7.7)\)
so it would be 4x=log(7.20)/log(7.7) ?
Yes, very good. Now, divide both sides by 4.
wait , how would i divide both sides by 4 if im already dividing the two logs ?
Multiply both sides by 1/4. Do it that way and let me know what you get.
x=log(7.7)/log(7.20)*0.25
i meant log(7.20)/log(7.7)
I would have written it like this just to be safe \[\large x = \frac{\log(7.20)}{4 \log(7.7)}\]
Now, you can use your calculator to figure out an approximate value of x
omigod , thank you so much !
so x=.86/3.55 = .24 ?
Yes, correct, although anytime you have a decimal answer like that, you should probably write \(x \approx .24\) since it is a decimal approximation.
Great job :D
thank you <333 .
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