Question

3x^3=24

Answer 1

\[24 = 2^3 * 3\]
so
\[3x^3 = 3*2^3\]
so x = ?

Answer 2

So I don't get it and the study guide said I need to use the quadratics formula and i don't get how to use the formula with a cubed equation.

Answer 3

Forget the study guide. I think quadratic formula is not useful here.

Answer 4

Oh but this is for an accuplacer test

Answer 5

if you are supposed to use the quadratic formula it must be 3x^2, not 3x^3 - right?

Answer 6

then you have
\[3x^2 - 24 = 0\]

and then you can solve it using the quadratic formula

Answer 7

No that's the thing Its 3x^24 so do I use the difference of cubes then use the quadratic formula?

Answer 8

Sorry 3x^3=24

Answer 9

ah, I think you are right
\[3(x^3 - 2^3) = 0\]\[(x-2)(x^2 - 2x + 4) = 0\]
Is that how it is maybe. But this only has 1 real solution.
I don't know. Sorry I can't help.

Answer 10

Thanks I got it there is a 1 real solution and also one for the quadratic formula but I don't know how to wright it on here but the answer guide sai it was right so thanks

Answer 11

So using the quadratic formula to solve for the complex roots:
(x2−2x+4)=0
a=1
b=-2
c=4
x=(-b +/- sqrt(b^2-4ac))/2a
=(2 +/- sqrt(4-16))/2
=1 +/- 2sqrt(3)i