Question

x power of 2 - x = 6

Answer 1

is this your question?:
\[\large{x^{2-x}=6}\] ?

Answer 2

or this?:
\[\large{x^2 - x=6}\]

Answer 3

x^2 -x = 6
x^2 -x -6 = 0
(x-3)(x+2) = 0 < - solve~

Answer 4

mathslover its the 2nd on you wrote.

Answer 5

\[\large{x^2-x=6}\]
\[\large{x^2-x-6=0}\]
right?

Answer 6

i dont understand, why would i equal it to 0?

Answer 7

x^2 -x = 6
Subtract 6 from both sides
x^2 -x - 6= 6 - 6
x^2 -x -6 = 0
Factor the expression
(x-3)(x+2) = 0
Put the factors = 0 and solve them.

Answer 8

see

\[\large \color {red} x = \color {green} 4\]

subtract 4 both sides

\[\large \color {red}x - 4 = \color {green} 4 - 4\]

\[\large \color {red}x - 4 = 0\]

similar is the case here.

Answer 9

\[\large x^2 - x = 6\]

subtract 6 both sides,

\[\large \color {red}{x^2 - x} - 6 = 6-6\]

\[\large \color {red}{x^2 - x- 6} = \color {green} 0\]

Answer 10

i understand that step, but i dont understand what comes next?

Answer 11

Now

\[\large x^2 - x - 6 = 0\]
\[\large x^2 - 3x + 2x - 2*3 = 0\]
\[\large x(x-3) + 2(x-3) = 0\]
\[\large (x+2)(x-3) = 0\]

clear ?

Answer 12

@kaitlingkanatsky