Question

2(ln(x)) + ln(x-1)= ln(2)
solve

Answer 1

\[2\left( \ln(x) + \ln(x-1) =\ln(2) \right)\]?

Answer 2

yes

Answer 3

well the 2 is outside of the brackets..
soo.. \(2ln(x) + 2ln(x-1) = ln(2)\)

Answer 4

ok so then do I combine them into a multiplication problem?

Answer 5

wait you can use log laws; no need to expand it

Answer 6

can you show me please?

Answer 7

would the 2ln just cancel?

Answer 8

\[2\left(\ln(x)(x-1\right) =\ln(2)\]

Answer 9

what is the difficule!! :it amounts to solve x^2-x-sqrt(2)=0

Answer 10

hmm \[\ln(x)(x-1)=\frac{\ln(2)}{2} \]

Answer 11

but its lohs where didyou get the x^2 from?

Answer 12

logs*

Answer 13

is the answer 1+ root5/2 and 1-root5/2?

Answer 14

we have ln[(x-1)x]=ln(sqrt(2))
we apply the funtion e^x on both
so you wil have x^2-x-sqrt(2)=0

Answer 15

how did you get the sqrt(2)

Answer 16

o no you were right i was just wondering how you get the part with the ln(sqrt2)?

Answer 17

it's a theorem ln(x^a)=a*ln(x)

Answer 18

do you understand

Answer 19

yes so in this case it you took the 2 (ln(x)) and made it 2*ln(x)?

Answer 20

yes

Answer 21

why did it end up on the other side?

Answer 22

i don't understand ,you mean why i didn't finish the calcul !!!!