Question

mole concept !

Answer 1

@waterineyes back here :)

Answer 2

Write your question here..

Answer 3

yea .. okay !

Answer 4

Calculate the mass of the following :
(a) 0.5 mole of CO2.
(b) 6.02 * 10^21 molecules of O2.
(c) 1 * 10^23 molecules of H2S.
(d) 56.8 L of SO2.
(e) 1.5 mole of H2SO4.

Answer 5

I had said to write question here not questions here ..

Ha ha ha..

Kidding..

Answer 6

i don't understand .. what did you want me to do actually ?

Answer 7

question means one question.

questions means more than one questions..

Leave it.

Answer 8

oh i din see the < S > !

Answer 9

its one question my teacher gave !

Answer 10

there are many questions like this .. and water will solve everything :p

Answer 11

i hope so !

Answer 12

Ha ha ha..

Answer 13

:)

Answer 14

so you know this ?

Answer 15

Yes...

Answer 16

so teach !

Answer 17

For fist part:

Find the molecular mass of \(CO_2\)..

Answer 18

*first..

Answer 19

molecular mass , mass and molar mass excluding the ( g ) all the same ?

Answer 20

I will say not to go this way..

Answer 21

then ?

Answer 22

See now you have studied What is Molar Mass..

Molar mass is mass of 1 mole of any substance.
If that substance is CO2

then:

Molar Mass is mass of 1 mole of CO2

So here basically you have to find Molar Mass..

For getting molar mass you will find the molecular mass of CO2 first same as you did for NaCl..

Answer 23

yeah okay .. so in the question we are asked to find the mass right ?

Answer 24

For atoms: we have atomic mass.

For molecules we have molecular mass..

Answer 25

okay !

Answer 26

Yes..
Molar mass is nothing but mass only.

Molar Mass is "Mass" of 1 mole of a substance in grams..

Answer 27

okay :)

Answer 28

so how to do (a) ?

Answer 29

mass of CO2 is 44 g ?

Answer 30

According to the definition of molar mass:

Molar mass is mass of 1 mole right ??

Answer 31

yeah !

Answer 32

But you have to find for 0.5 mole..

This you got mass for 1 mole..

can you find?

for 1 mole it is 44g

for 0.5 or half it will be ??

Answer 33

0.5 * 44 / 1 ?

Answer 34

right ?

Answer 35

Yep..

Answer 36

okay :)

Answer 37

Think logically also..

For 1 it is 44g

for half that is 0.5 is nothing but half of 1:

for 0.5 it will be 44/2 = 22g.

Getting ??

Answer 38

partially !

Answer 39

yea yea .. on second thinking i understood !

Answer 40

i forgot half of 1 is 0.5 !

Answer 41

0.5 is 1/2 no ??

Answer 42

yea i got it !

Answer 43

This solves first one..

Getting ??

Answer 44

dont laugh !

Answer 45

yeah :)

Answer 46

Ha ha ha ha..

Not I am not..

Ha ha ha..

Answer 47

lol yu are !

Answer 48

okay .. best medicine .. so laugh !

Answer 49

e> part is same..

Can you do that ??

Answer 50

let me try !

Answer 51

Take your time..

Answer 52

mass of 6.023 * 10^23 molecules of O2 = 32
mass of 6.02 * 10^21 molecules of O2 = x
cross multiply ?

Answer 53

Go for last part..

e) part

Answer 54

okay !

Answer 55

This I tell you later on..

Answer 56

okay !

Answer 57

e part is same as a part.

Just try that so that you will completely get it..

Answer 58

mass of 1 mole of CO2 = 44 g
mass of 1.5 mole of CO2 = ?

44 * 1.5 / 1 = 66 g

Answer 59

@waterineyes

Answer 60

wrong ?

Answer 61

Yes concept is right..

Answer 62

Dear there is H2SO4 not CO2...

Answer 63

oh .. sorry !

Answer 64

okay let me do with H2SO4

Answer 65

Do the same for H2SO4..

Answer 66

I am in no hurry take your time..

Answer 67

Atomic Mass of H is : 1
Atomic Mass of S is : 28
Atomic Mass of O is : 16..

Answer 68

mass of 1 mole of H2SO4 = 98 g
mass of 1.5 mole of H2SO4 = x

= 98 * 1.5 / 1
= 147 g

Answer 69

atomic mass of s = 32 or 28 ?

Answer 70

@waterineyes there ?

Answer 71

I think you are right..

Answer 72

My mistake : Atomic Mass of Sulphur is 32..

Answer 73

okay !

Answer 74

Yes you have done that correctly:

98 + 49 = 147 g...

Answer 75

okay .. :)

Answer 76

Now we will do second part b)..

Answer 77

okay !

Answer 78

but i did that before right ?

Answer 79

is that wrong ?

Answer 80

Yes somewhat wrong..

Answer 81

okay .. so teach me :)

Answer 82

Sere have you remembered this:

\[1 Mole (oxygen) = 6.023 \times 10^{23} \; Oxygen \; \; Molecules\]

Answer 83

okay

Answer 84

then .. how to do ? are you trying ?

Answer 85

Oh really very sorry..
You were doing it right

Answer 86

really ?

Answer 87

\[6.023 \times 10^{23} \implies 32g\]

\[1 \implies \frac{32}{6.023 \times 10^{23}}\]

\[6.023 \times 10^{21} \implies \frac{32}{6.023 \times 10^{232}} \times 6.023 \times 10^{21} = ??\]

Answer 88

Oh sorry there is mistake in denominator there power of 10 is 23 and not 232..

Answer 89

okay ..

Answer 90

There is mistake in denominator 10 has power 23 and not 232..

Answer 91

yeah you did mention it above !

Answer 92

so 32/100 = 0.32g ?

Answer 93

Yes you were going right @ashna

Do it in your way if you did not understand my way..

Answer 94

no both seems the same .. i can understand :)

Answer 95

Yep you are right..

Answer 96

Now c part is same as b..