completely factor the polynomial8x^3+56x^2+8x+56=

Question

mathslover · Answer

first find the factors of 56

anonymous · Answer

The factors of 56 are 1, 2, 4, 7, 8, 14, 28 and 56.

mathslover · Answer

are -1 , -2 , -4 , -7 , -8 , -14 , -28 and -56 also factors of 56?

vishweshshrimali5 · Answer

$$\large 8x^3 + 56 x^2 + 8x + 56$$

$$\large 8(x^3 + 7x^2 + x + 7)$$

$$\large 8(x^2(x + 7) + 1(x+7)$$

$$\large 8(x^2 + 1)(x+7)$$

mathslover · Answer

yes that is also the method but easier though

I was going to solve it with factor theorem

vishweshshrimali5 · Answer

:)

vishweshshrimali5 · Answer

@jlmack07

anonymous · Answer

well yes bu this is a positive number so we are dealking with positive correct

mathslover · Answer

put x = -7 

you will get that p(x)= 0

that is it is the zero of the polynomial p(x) 

that is x+7 is the factor of p(x) 

divide p(x) by x+7 now|dw:1345177646774:dw|