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Mathematics 18 Online
OpenStudy (anonymous):

completely factor the polynomial8x^3+56x^2+8x+56=

mathslover (mathslover):

first find the factors of 56

OpenStudy (anonymous):

The factors of 56 are 1, 2, 4, 7, 8, 14, 28 and 56.

mathslover (mathslover):

are -1 , -2 , -4 , -7 , -8 , -14 , -28 and -56 also factors of 56?

OpenStudy (vishweshshrimali5):

\[\large 8x^3 + 56 x^2 + 8x + 56\] \[\large 8(x^3 + 7x^2 + x + 7)\] \[\large 8(x^2(x + 7) + 1(x+7)\] \[\large 8(x^2 + 1)(x+7)\]

mathslover (mathslover):

yes that is also the method but easier though I was going to solve it with factor theorem

OpenStudy (vishweshshrimali5):

:)

OpenStudy (vishweshshrimali5):

@jlmack07

OpenStudy (anonymous):

well yes bu this is a positive number so we are dealking with positive correct

mathslover (mathslover):

put x = -7 you will get that p(x)= 0 that is it is the zero of the polynomial p(x) that is x+7 is the factor of p(x) divide p(x) by x+7 now|dw:1345177646774:dw|

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