Express y as a function of x. What is the domain? a) log 3 + log y = log (x+2) - log x
log a + log b = log(ab)
i strongly suggest you put everything as one log first
and log a - log b = log (a/b)
log(y)=log(x+2)-log(x)-log(3) log(y)=log(x+2)-(log(x)+log(3)) log(y)=log(x+2)-(log3x) log(y)=log((x+2)/3x) exponentiating both sides y = (x+2)/3x domain is all real x except x =0 i think im wrong
log (3y) = log (\(\cfrac{x+2}{x}\))
3y = \(\cfrac{x+2}{x}\) y = \(\cfrac{x+2}{3x}\)
Extremity you're close the answer is: {x< -2 or x > 0}
I'm confused about the domain though..
oh whoops, dangerous (x+2)/3x > 0 , since log has to always be positive that means (x+2)3x>0 (x+2)x>0 graph a parabola and you see that x<-2 and x>0 point is, when you make y the subject, you remove a fundamental analysis on the equation. that is, the presence of the log, and so the domain is what it is
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