Question

Find the lowest common denominator of the following fractions.

Answer 1

and

Answer 2

i got 24(y^2- 1)(y + 1)

Answer 3

Does it help if I tell you that y^2 - 1 = (y+1)(y-1)?

Answer 4

24(y^2- 1)?

Answer 5

the second fraction simplifies to \[\frac{ 7 }{ 8(y+1) }\] and the first to \[\frac{ y+5 }{ 6(y+1)(y-1) }\]
The common denominator in each fraction is 2(y+1). Do you see why this is?

Answer 6

yep

Answer 7

so its 24(y^2- 1).

Answer 8

@Traxter ?

Answer 9

Sorry, you're asked to find the lowest common denominator, i.e. the highest common factor that appears in both of the denominators. The denominators are 8(y+1) and 6(y+1)(y-1). We have a (y+1) in both of the fractions, and the highest number that they are both being multiplied by is 2, since 8=2x2x2 and 6=2x3. Does this make more sense now? Sorry for the slow reply.

Answer 10

okay thanks, i got it:D

Answer 11

Well done :)