Can someone check? Please and thank you!
An ellipse has foci at (–1, 1) and (–1, –7). The major axis is 12 units long. Show work for all answers.
-Determine the center of the ellipse.
-Determine the vertices of the ellipse.
-Find the equation of the ellipse.
I got (-1, -3) as the center.
(6,0) and (-6, 0) for the vertices
and y^2/ 36 + X^2/ 20 = 1
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mathslover (mathslover):
Sorry not so good in this topic :'(
OpenStudy (anonymous):
its okay! thanks anyways! :)
OpenStudy (anonymous):
and i just did these types of problems in summer school... smh
OpenStudy (anonymous):
haha am i doing them right?
OpenStudy (anonymous):
so the major axis is y, 6 high and 6 low...thinking
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OpenStudy (anonymous):
i m unsure about the vertices!
OpenStudy (anonymous):
hold on its coming back to me lol
OpenStudy (anonymous):
hahaha!
OpenStudy (anonymous):
this graph is shifted to the left -1 so shouldnt your answer be in the (y+1)^2 + (x+1)^2
OpenStudy (anonymous):
form
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OpenStudy (anonymous):
i always get confused about that! but i think it said its in x^2/ a^2 form? which one makes sense?
OpenStudy (anonymous):
if your center was at (0,0) then it would be x^2 + y^2 = 1, but this is shifted to it has to be the other form
OpenStudy (anonymous):
oh ok! so how can i change it to the other form?
OpenStudy (anonymous):
simply change the numerator to (x+1)^2
OpenStudy (anonymous):
you might leave the y^2 alone i cant remember
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OpenStudy (anonymous):
id literally have to dig through some of my notes to get you the right answer tho lol
OpenStudy (anonymous):
oh haha i wish i had some notes i could look at!
OpenStudy (anonymous):
i might be able to send you something hold up
OpenStudy (anonymous):
may I share Salman Khan's video tutorial on focuses of ellipse?
OpenStudy (anonymous):
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