Mathematics
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OpenStudy (anonymous):
another where did i go wrong:
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OpenStudy (anonymous):
Before posting and solving the question you went wrong??
This is strange..
OpenStudy (anonymous):
*go
OpenStudy (angela210793):
he went wrong while thinking how to solve it @waterineyes :P
OpenStudy (lgbasallote):
ahh glad to see the old gang together again
OpenStudy (anonymous):
look now you draw a huge crowd lol
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OpenStudy (angela210793):
@waterineyes excuse me?
OpenStudy (anonymous):
theres no pressure tho be cool
OpenStudy (anonymous):
\[10^{2} \times 10^{\frac{ 1 }{ 2}} \times 10^{\frac{ -1 }{ 3 }} \times10^{-6} \times 10^{x}\times10^{\frac{ -1 }{ 2}x}\]
OpenStudy (anonymous):
people please, i am not providing entertainment just looking for answers
OpenStudy (anonymous):
Try it once..
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OpenStudy (anonymous):
yes i'll
OpenStudy (anonymous):
wait angela
OpenStudy (angela210793):
there was a ?=question mark at the end if u didn't notice @waterineyes
OpenStudy (anonymous):
oh okay
OpenStudy (angela210793):
I thought so..
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OpenStudy (anonymous):
10^2 x 10^1/2 x10^-1/3 x10^-6 = \[\frac{ 10^{\frac{ 5 }{ 2 }} }{ 10^{\frac{ -19 }{ 3 }} }\]
10^x X 10^-1/2x =\[\frac{ 10^{x} }{ 10^{\frac{ 1 }{ 2}x} }\]
OpenStudy (anonymous):
good so farr?
OpenStudy (anonymous):
See it will be easier if you add all the powers first...
OpenStudy (anonymous):
oh okay
OpenStudy (anonymous):
\[\large x^a \times x^b \times x^c \times x^d \times x^e \implies x^{a + b+c+d+e}\]
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OpenStudy (anonymous):
No need to write the base just add all the powers first...
OpenStudy (anonymous):
2+1/1-1/3-6= \[\frac{ 6+3-2-6 }{ 6 } = \frac{ 1 }{ 6}\]
OpenStudy (anonymous):
wait
OpenStudy (anonymous):
\[2 + \frac{1}{2} - \frac{1}{3} - 6 = ??\]
OpenStudy (anonymous):
Take your time..
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OpenStudy (anonymous):
common denominator: 6
\[\frac{ 6+3-2-6 }{ 6}\]
OpenStudy (anonymous):
isn't it?
OpenStudy (anonymous):
Check for last part that is 6..
OpenStudy (anonymous):
ah
OpenStudy (anonymous):
-36
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OpenStudy (anonymous):
make the common denominator for 6 also..
OpenStudy (anonymous):
Yep.. -36
OpenStudy (anonymous):
Now solve it..
OpenStudy (anonymous):
9-38/6= 29/6
OpenStudy (anonymous):
-29
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OpenStudy (anonymous):
Yep...
OpenStudy (anonymous):
Now:
\[x - \frac{1}{2}x = ??\]
OpenStudy (anonymous):
1/2x
OpenStudy (anonymous):
So what do you get now ??
OpenStudy (anonymous):
Write it in powers of 10 ..
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OpenStudy (anonymous):
10^-29/6+1/2x
OpenStudy (anonymous):
but thats wrong..
OpenStudy (anonymous):
my book says 10^-23/6+3/2x
OpenStudy (anonymous):
More clearly:
\[\large 10^{{\frac{1}{2}}x + \frac{29}{6}}\]
OpenStudy (anonymous):
Then we have to check it again..
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OpenStudy (anonymous):
unless the book is wrong..
OpenStudy (anonymous):
x - 1/2x = 1/2 x
It can't be 3/2x unless x + 1/2x is there..
OpenStudy (anonymous):
wait i didn't see the last power right its 10^1/2x
OpenStudy (anonymous):
so the 3/2x is accounted for
OpenStudy (anonymous):
Sorry I did mistake of minus here:
\[\large 10^{{\frac{1}{2}}x - \frac{29}{6}}\]
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OpenStudy (anonymous):
In that case it has become now:
\[\large 10^{{\frac{3}{2}}x - \frac{29}{6}}\]
OpenStudy (anonymous):
but the fraction is still -23/6
OpenStudy (anonymous):
We have calculated it right..
May be misprint in book..
OpenStudy (anonymous):
Let me check the powers by which we will get -23/6..
OpenStudy (anonymous):
i guess book misprint :) thank you
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OpenStudy (anonymous):
Is your question right ??
OpenStudy (anonymous):
yes, i corrected the last power
OpenStudy (anonymous):
No no except that..
OpenStudy (anonymous):
everything else is right
OpenStudy (anonymous):
If you multiply one 10 with your question then you will get -23/6
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OpenStudy (anonymous):
-29/6 + 1 = -23/6
Ha ha ha
Nevermind..
Book misprint..
OpenStudy (anonymous):
yep