Question

find all real numbers that satisfy the equation
|1-3x|=3

Answer 1

sin is negative in the third and fourth quadrants



in the third quadrant, sin 240--sqrt(3)/2
in the fourth quadrant, sin 300=-sqrt(3)/2, so the angles are 240 and 300 deg, or 4pi/3 and 5 pi/3 radians

you can have an infinite number of answers to this, if you remember that sin is 2 pi periodic, so your complete answer set is

4 pi /3 + 2 n pi
5 pi/3 + 2 n pi where n is an integer

Answer 2

@abayomi12 what are u doing?

Answer 3

the answer is -2/3 and 4/3, but i dont know how to get there, your methode cis not quite those values ar least not that i can interpert
calculus

Answer 4

I1-3xI=3
SO,
1-3x=3 and
1-3x=-3

Answer 5

Can u solve that two equations

Answer 6

sauravshakya have a look back at the answer i gave a moment ago

Answer 7

no

Answer 8

1-3x=3 and
1-3x=-3

Answer 9

WE need to solve that

Answer 10

am doing thing

Answer 11

1-3x=3
3x=1-3
3x=-2
x=-2/3

Answer 12

which is one solution

Answer 13

my answer is the same with yours just the method is different

Answer 14

now, solve 1-3x=-3

Answer 15

to get another answer

Answer 16

sauravshakya im a fan

Answer 17

@lgbasallote did u understand what @abayomi12 did

Answer 18

no

Answer 19

yeah

Answer 20

can u get another solution @sparksaflyen

Answer 21

no

Answer 22

i will for that

Answer 23

solve 1-3x=-3

Answer 24

can u?

Answer 25

a minute trying to get another method

Answer 26

yeah i will but trying to get another

Answer 27

the results werent the same

Answer 28

thats right thanks, obviously its because im working with absolute values

Answer 29

btw i was referring to wha @sauravshakya said to me

Answer 30

First you need to distribute (multiply 1/3 by x and -3). This will give you

1/3x-1<(x-2)/4 I'm assuming that x-2 is all over 4 on the right side.

Then you'll have to multply