Question

How do you find the vertices of a hyperbola?

Answer 1

center +- whichever part is NOT subtraction

Answer 2

wait which center do you use? x or y?

Answer 3

heres my problem: (y-4)^2/121-(x+9)^2/144=1

Answer 4

center is defined as (x,y)

this would be easier to expalin with an example if you have one ... there it is :)

Answer 5

notice that the x parts are subtracting; so our transverse axis is paralell to the y axis

Answer 6

right..

Answer 7

when we zero out the x part to define the vertexes along the y we get:

(y-4)^2/121 = 1

(y-4)^2 = 121

y-4 = +- sqrt(121)

y = 4 +- 11

Answer 8

both point use the same x part from the center point to define them

Answer 9

okay.. so now what? Do you put 4+-11. which is -9 and 15

Answer 10

so those are my y values in the vertices?

Answer 11

those are the y values yes; all we need to do is determine the x value for them

Answer 12

and how do we do that?

Answer 13

take your x portion of the hyper and equate it to zero

(x+9) = 0

then solve for x

Answer 14

x=-9 in both of the vertices?

Answer 15

yes, since we are moving along parallel to the y axis; the x values remian unchanged

Answer 16

so my answer is (-9,15) and (-9,-7)?

Answer 17

those are the only two with both x values as -9

Answer 18

yes

Answer 19

okay thankyouuu so much!!