Question

The area of the front face of the analog clock shown below is 153.86 square inches. The length of the minute hand is 0.2 inches less than the radius of the front face.



What is the length of the arc, rounded to the nearest hundredth of an inch, the minute hand makes when it moves from the number 8 to the number 2 on the clock?

http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0810_12/image0044e68c4f6.jpg

Answer 1

did u googled it?:)

Answer 2

I did. I don't want the answer. I want to understand. >.<

Answer 3

oh ok thats good well let me see what i can do

Answer 4

flvs sucks doesnt it !

Answer 5

word

Answer 6

153. 86 = pi r^2
r = \[\sqrt{153.86/\pi}\]

Answer 7

It does. Geometry sucks.. period. No matter where you do it.

Answer 8

Amen To that ! ^^

Answer 9

yeah im taking geometry to lol hope u figure it out

Answer 10

@annas it would be 7?

Answer 11

then,
minus 0.2 inches from the radius to have the length of the minute hand
the minute hand will move through 180 degrees / pi radians when it moves from 8 to 2
the arc length will be half the circumference of the circle with radius of the minute hand.....
hope this will work

Answer 12

dont have a calcutator right now so solve it your self

Answer 13

10.68 inches

3.56 inches

6.80 inches

21.35 inches

These are my answer choices. That doesn't work :l

Answer 14

Well, the answer I put on the exam in module 8 of flvs was 21.35 inches. Do you know how to caculate it?

Answer 15

Did you get it right though @Veelution

Answer 16

yes

Answer 17

Do you know how to calculate though? Thats most important