The area of the front face of the analog clock shown below is 153.86 square inches. The length of the minute hand is 0.2 inches less than the radius of the front face. What is the length of the arc, rounded to the nearest hundredth of an inch, the minute hand makes when it moves from the number 8 to the number 2 on the clock? http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0810_12/image0044e68c4f6.jpg

6 years agodid u googled it?:)

6 years agoI did. I don't want the answer. I want to understand. >.<

6 years agooh ok thats good well let me see what i can do

6 years agoflvs sucks doesnt it !

6 years agoword

6 years ago153. 86 = pi r^2 r = \[\sqrt{153.86/\pi}\]

6 years agoIt does. Geometry sucks.. period. No matter where you do it.

6 years agoAmen To that ! ^^

6 years agoyeah im taking geometry to lol hope u figure it out

6 years ago@annas it would be 7?

6 years agothen, minus 0.2 inches from the radius to have the length of the minute hand the minute hand will move through 180 degrees / pi radians when it moves from 8 to 2 the arc length will be half the circumference of the circle with radius of the minute hand..... hope this will work

6 years agodont have a calcutator right now so solve it your self

6 years ago10.68 inches 3.56 inches 6.80 inches 21.35 inches These are my answer choices. That doesn't work :l

6 years agoWell, the answer I put on the exam in module 8 of flvs was 21.35 inches. Do you know how to caculate it?

6 years agoDid you get it right though @Veelution

6 years agoyes

6 years agoDo you know how to calculate though? Thats most important

6 years ago