Question

given:
x=2 y=0 find (r,theta)

Answer 1

r= \[\sqrt{x ^{2}+y ^{2}} = \sqrt{4}=2\]
\[\theta =?\]

Answer 2

x=r cos theta
y=r sin theta
theta =tan inverse of (y/x)

Answer 3

but what if i don't know the value of tan inverse @hartnn because we arent allowed calculators in the exam

Answer 4

here tan inverse of 0 is 0----> this is easy
but you have r value
so u can use x=r cos theta or y=r sin theta to get theta,if u can find sin inverse or cos inverse without calcy
atleast 1 of sin or cos or tan inverse is must for theta

Answer 5

ah okay, thank you for telling me about tan inverse zero, makes working easier

Answer 6

so \[\Theta = 0\]

Answer 7

yes,theta = 0