Determine the type of boundary line and shading for the graph of the inequality -3x - y > -6 Dashed line with shading on the side that includes the origin. Solid line with shading on the side that does not include the origin. Dashed line with shading on the side that does not include the origin. Solid line with shading on the side that includes the origin.
Solve for y. What do you get?
Set x=0 to solve for y and set y=0 to solve for x and then plot...
y<-3x-6
you draw a solid boundary line when it is greater than or equal to or less than or equal to and a dashed boundary line when it is greater than or less than
close, it's really y < -3x+ 6
Plug in the point (0,0) to see if your inequality is true or false.
Now graph y = -3x+6 That "less than" in y < -3x + 6 tells you to shade below the line The line is a dashed line because we're NOT including the boundary (since we don't have "or equal to" part thrown in)
Dashed line with shading on the side that includes the origin. my bad hopefully
ok
wait! omg... the inequality is not true so we do not include the origin 0 is not greater than 4.. :)
y < -3x+ 6 0 < -3(0)+ 6 0 < 0 + 6 0 < 6 So you include the origin
since that last inequality is true
ohhhhhhh ok
I prefer graphing the line y = -3x+6, then shading below it
ok
bye
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