OpenStudy (anonymous):

Solve Radical x + 14 - 12 = x

6 years ago
OpenStudy (anonymous):

6 years ago
OpenStudy (anonymous):

$\sqrt{x + 14} - 12 = x$

6 years ago
OpenStudy (anonymous):

just take 12 right side and square both the sides

6 years ago
OpenStudy (anonymous):

you will get a quadratic equation

6 years ago
OpenStudy (anonymous):

calculate its roots

6 years ago
OpenStudy (anonymous):

is that ok for u

6 years ago
OpenStudy (australopithecus):

$(x+14)^{\frac{1}{2}} = x + 12$ $(x+14)^{\frac{1}{2}*2} = (x + 12)^2$ $(x+14)^1 = (x + 12)^2$ $x+14 = (x + 12)^2$

6 years ago
OpenStudy (anonymous):

My Choices Are X = -10 X - -13 X =-10 & -13 And None Of The Above . . . So Im Assuming Its None Of The Above

6 years ago
OpenStudy (australopithecus):

dont assume

6 years ago
OpenStudy (australopithecus):

do you not follow my algebra

6 years ago
OpenStudy (australopithecus):

Just look at it and try to understand

6 years ago
OpenStudy (australopithecus):

do you not know how to expand $x + 14 = (x+12)(x+12)$

6 years ago
OpenStudy (australopithecus):

(a+b)(a+b) = a^2 + ab + ab + bb

6 years ago