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Rationalize the denominator of
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\[\sqrt{-36} \over (2-3i) + (3 +2i)\]
first,to simplify,combine like terms in denominator (2-3i)+(3+2i)=2+3+2i-3i=5-i got this?
I Got That
now complex conjugate of 5-i is 5+i to rationalize the denom,you multiply by complex conjugate(5+i) in both numerator and denominator \[\frac{\sqrt{-36}}{5-i}\frac{5+i}{5+i}\] get this step?
Alrightt , I Got That
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now u know that (a+bi)(a-bi)=a^2+b^2 so (5+i)(5-i)=25+1=26
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