OpenStudy (anonymous):

The sum of five different positive integers is 100. If the smallest of these integers is 10, what is the larges possible value of one of the other four integers?

6 years ago
jimthompson5910 (jim_thompson5910):

The smallest integer is 10. So the other four numbers add to 100 - 10 = 90

6 years ago
OpenStudy (anonymous):

Is it that simple???

6 years ago
jimthompson5910 (jim_thompson5910):

If x, y, z and w are the four numbers, then x+y+z+w = 90

6 years ago
jimthompson5910 (jim_thompson5910):

Now make x as large as possible

6 years ago
jimthompson5910 (jim_thompson5910):

the answer isn't 90, but it helps get you the answer

6 years ago
OpenStudy (anonymous):

How do you find it when you don't even know one of the letters?

6 years ago
jimthompson5910 (jim_thompson5910):

Let's make x as large as possible

6 years ago
jimthompson5910 (jim_thompson5910):

Can x = 90?

6 years ago
OpenStudy (anonymous):

Yes, right?

6 years ago
jimthompson5910 (jim_thompson5910):

but that would make y, z, and w all be 0

6 years ago
jimthompson5910 (jim_thompson5910):

x+y+z+w = 90 90+0+0+0 = 90

6 years ago
OpenStudy (anonymous):

So 84?

6 years ago
jimthompson5910 (jim_thompson5910):

good, x+y+z+w = 90 84 + 1 + 2 + 3 = 90

6 years ago
jimthompson5910 (jim_thompson5910):

anything larger for x would make y, z, or w have to become smaller (and either not be positive, or not be different)

6 years ago
OpenStudy (anonymous):

Thank you!! I appreciate it a lot

6 years ago
jimthompson5910 (jim_thompson5910):

you're welcome

6 years ago
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