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(5b) ^-2
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Similar Example: \[\Large (6z)^{-2} = \frac{1}{(6z)^2}\] \[\Large (6z)^{-2} = \frac{1}{36z^2}\]
thanks so it would be 1/25b^2
yes, the answer to your question is \[\Large \frac{1}{25b^2}\]
thank! I have one more, (-6p)^4
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