(5b) ^-2
6 years agoSimilar Example: \[\Large (6z)^{-2} = \frac{1}{(6z)^2}\] \[\Large (6z)^{-2} = \frac{1}{36z^2}\]
6 years agothanks so it would be 1/25b^2
6 years agoyes, the answer to your question is \[\Large \frac{1}{25b^2}\]
6 years agothank! I have one more, (-6p)^4
6 years ago