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Mathematics 9 Online
OpenStudy (anonymous):

given (x,y) what is (r,theta)?

hartnn (hartnn):

r=\[\sqrt{x ^{2}+y ^{2}}\] \[\theta=\tan^{-1} (y/x)\]

OpenStudy (anonymous):

\[x= -\sqrt{3} \] y=1 r=\[\sqrt{x ^{2}+y ^{2}}=2\] \[\theta=\tan^{-1} \frac{ 1 }{ -\sqrt{3} }\]= -30° but \[\theta \]'s absoluet value should be the least and the answer in the book is 150° but idk how

hartnn (hartnn):

150 seems to be incorrect,because -30 lies in 4th quadrant and equals 360-30=330 degrees , and if u want least absolute value its -30 only

OpenStudy (anonymous):

i don't know the book said 150° :(

OpenStudy (anonymous):

i guess its wrong.. thx anyway :)

hartnn (hartnn):

well,as per my thoughts now, they have used that tan has period of 180 degres that is tan(theta)=tan (180+ theta) so tan (-30)=tan(180-30)=tan 150

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