an automobile traveling 30.0 m/s has wheels of 0.750 m diameter. (a) what is the angular speed of the wheels about the axle? (b) if the car is brought to a stop uniformly in 10.0 s, what is the angular acceleration? (c) How many times do the wheels turn during thus braking period?
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OpenStudy (anonymous):
\[a = -3m/s^2\]
OpenStudy (anonymous):
\[aT = \alpha r\]
OpenStudy (anonymous):
\[= -3 * 0.75/ 2 = -1.125\]
OpenStudy (anonymous):
\[s = ut + 1/2 a t^2\]
OpenStudy (anonymous):
\[= 300 - 1/2 * 1.25 * 10 * 10 = 243.75\]
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OpenStudy (anonymous):
@shubhamsrg @ajprincess
OpenStudy (anonymous):
\[2 * 3.14 * 0.375 = 2.3\]
OpenStudy (anonymous):
= 2.355
OpenStudy (anonymous):
@sarahvince Do u have the answer key???
OpenStudy (anonymous):
yes thank you
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OpenStudy (anonymous):
so the answer in letter c is 2,355?
OpenStudy (anonymous):
i am not sure of my answers
OpenStudy (anonymous):
No : of rotations = n * Circumfrence = Distance covered
OpenStudy (anonymous):
im confused hehehe
OpenStudy (anonymous):
Do u knw abt Circular Motion??
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OpenStudy (anonymous):
yes thats our latest lesson
OpenStudy (anonymous):
Do u knw angular velocity , centripetal acceleartion
OpenStudy (anonymous):
i just want to makes ure my answers are correct. hehehe