Question

A body of mass 2 kg at O has an initial velocity of 3m/s along OE and it is subjected to a force of 4N perpendicular to OE the distance covered in 4 seconds?

Answer 1

@shubhamsrg @ajprincess @hartnn

Answer 2

The answer should be 20

Answer 3

force along OE =0
thus ,velocity in OE direction is constant = 3
force along OF =4N.
mass of body=2kg.
acceleration=4/2=2
distance moved by the body in OE in 4secs =vt=3.4=12m.
distance moved by the body in OE in 4secs =ut+at^2/2=0+16=16m.
net distance = sqrt(12^2 + 16^2) = 20