Question

A rocket is fired vertically upward and it is s feet above the ground in t seconds after being fixed, where s = 560t-16t^2 and the positive direction is upward. How long it takes for the rocket to reach its hmax(maximum height)?

Answer 1

take derivative

Answer 2

ok...wait there

Answer 3

35/2? @mandonut ??

Answer 4

that is t

Answer 5

at 17.5 sec it reaches max height

Answer 6

ya that is answer

Answer 7

i thought you was looking for max height

Answer 8

ok...thanks!
i have another question..

Answer 9

find the relative minimum value of the function y=x^3-3x^2+1

Answer 10

take derivative and equal to 0

Answer 11

to find zeros of function

Answer 12

x=2 is that right??

Answer 13

and 0

Answer 14

these two points are critical points where min or max may exists

Answer 15

plug in values between each interval into the derivative equation

Answer 16

if its negative draw an arrow down and if its positive draw arrow up

Answer 17

so plug in a value between (-infinity and 0), (0 to 2), and (2 to infinity)

Answer 18

ok...
If the sum of 2 nos. is s find the minimum value of the sum of their squares..